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![]() The second is by using the replace() method of string class. The first approach is by splitting the string into two halves to remove the i-th character. 1 You can use a simple regex to match any text between the slashes: str str.replaceAll ('/ /+/ /+', '') Or you can split and rejoin like this: String parts str.split ('/') str String.join ('/', Arrays.asList (parts).subList (0, parts. ![]() We have seen two different approaches for removing the i-th character in a string. In the function, since indexing in a string starts with 0, to remove i-th character, we have to pass i-1 as an index. ![]() When the character is found replace it with an empty string. We have used a for loop in our program to traverse the string and get the character at the index i. Look at the program to understand the implementation of the above-mentioned approach. Step 6- Print value returned by the function Python Program 2 Step 4- If found replace the character at index i with an empty string Step 3- Check if the current iteration is equal to the index i Step 2- Run a loop from 0 to the length of the string The following Java program demonstrates how this can be achieved. For example, let us assume we have string '1,2,3,4,5' and we want to remove '3,' from it to get the new string '1,2,4,5'. Step 1- Define a function that will accept the string and index i and will remove the character at i One of the common text processing requirements is to remove a specific substring from a given string. It returns a copy of the string after replacing all the occurrences of the old substring with the new substring. In this method, we will replace the character at the i-th index with an empty substring given as ("") using the replace() method. Pythnisgood Approach 2: using replace() method Since, indexing in a string starts with 0, to remove i-th character, we have to pass i-1 as an index in our function. We have sliced the string into two substrings and stored each substring in another variable then we have joined the two substrings using the concatenation operator (+). Step 5- print value returned by the function Python Program 1 Step 4- Join both substrings and return the joined string Step 3- Another variable will store the characters after the i-th index Step 2- In the function, declare a variable that will store characters before the i-th index Step 1- Define a function that will accept a string and index i Algorithmįollow the algorithm to understand the approach better. Slicing specifies how to slice a sequence into smaller objects where the starting and ending index is specified by us. This article is created to cover a program in Java that removes particular word from a given string, entered by user at run-time of the program. ![]() So, a manual effort is required to negate the effect of the case either by applying the toLowerCase () or toUpperCase () methods. Can you solve this real interview question Remove All Occurrences of a Substring - Given two strings s and part, perform the following operation on s until. startsWithIgnoreCase () Method The startsWith () method is case-sensitive. To split the string we will use the concept of slicing. Once existence is confirmed, then we can also use the substring () method to remove it: trimPrefix.substring ( Groovy. Then we can join these two strings to get the string that will not have the i-th character. In this approach, we will split the string into two halves, one before index i and the other after index i. We will be discussing each approach in detail. To solve this problem in Python we can follow these approaches Let us look at the sample input and output of the program. For a given string, we have to remove the character present at the i-th index in the string. Strings in Python are a sequence of characters wrapped in single, double, or triple quotes. In this tutorial, we will learn to remove the i-th character from a string in Python. ![]() ![]() ![]()
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